IF and elif and else

#!/usr/bin/python
import sys

# By default argument will count script name also so I have reduced -1 for exact value
arg_count = len(sys.argv) - 1

#print what I have entered in arguments"
print "\nYou have entered ",arg_count, "arguments", sys.argv[1],",", sys.argv[2]

# Store Argurments in variable
Arg_first = sys.argv[1]
print "\nType of first argument is ", type(Arg_first)

# store second arg in variable
Arg_Sec  =  sys.argv[2]
print "\nType of second argument is", type(Arg_Sec)

#By default argement will be in string type so converting in integer for mathematical
a = int(Arg_first)
print "\nAfter converting argument type is", type(a)

b = int(Arg_Sec)
print "After converting second argument type is", type(b)

if a == b:
        print "\nAddition of Argument 1 and Argument 2 is", a + b
elif a < b:
        print "\nMultiple of Arg1 and Arg2 is", a * b
elif a > b:
        print "\nDivide the arg1 and agr2 is", a / b
else:
        print "I am wrong"


Output:
[root@mysql Scripts]# python if.py 4 2

You have entered  2 arguments 4 , 2

Type of first argument is 

Type of second argument is

After converting argument type is
After converting second argument type is

Divide the arg1 and agr2 is 2
[root@mysql Scripts]# python if.py 4 8

You have entered  2 arguments 4 , 8

Type of first argument is 

Type of second argument is

After converting argument type is
After converting second argument type is

Multiple of Arg1 and Arg2 is 32
[root@mysql Scripts]# python if.py 9 9

You have entered  2 arguments 9 , 9

Type of first argument is 

Type of second argument is

After converting argument type is
After converting second argument type is

Addition of Argument 1 and Argument 2 is 18